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  1. What is the product of the following reaction? 1)CH_3 OH - Socratic

    Dec 23, 2017 · These are ostensibly acid-base reactions.... For ammonium we could write.... NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed ...

  2. Question #cf988 - Socratic

    DeltaH = +"12.2 kJ" Yes, you are correct. The molar enthalpy of vaporization, or simply the enthalpy of vaporization, tells you the enthalpy change that occurs when one mole of a substance goes from …

  3. Can you give the IUPAC name for the following (CH_3)_3C-OH

    Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2 …

  4. Question #54b11 - Socratic

    The balanced equation is "CH"_3"CH"_2"COO"^"-" + "3S" + 4"OH"^"-" → "CH"_3"COO"^"-" + "HCO"_3^"-" + "3HS"^"-" + "H"_2"O" > The reaction is carried out at pH 8, so we must balance in …

  5. Question #851e9 + Example - Socratic

    The equation for this is: H^+ (aq)+OH^ (-) (aq)rightleftharpoonsH_2O (l) A common example of a neutralization reaction would be adding hydrochloric acid to aqueous sodium hydroxide.

  6. Question #7c802 + Example - Socratic

    Oxides that form neither an acid nor a base, in combination with water. Acid oxides will react with water to ultimately give off H^+: Sulphur trioxide SO_3 will form sulfuric acid: SO_3 (g) + H_2O (l) …

  7. Question #22e51 - Socratic

    Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water.. But; Cu (OH)_2 + HCl -> CuCl_2 + H_2O " [Not Balanced]" Balancing the equation..

  8. Question #019dd - Socratic

    Only (C) is fully correct. As you can see, steam typically reacts with alkenes by adding H on one double-bonded atom and OH on the other. But there are two possible choices for which atom gets the single …

  9. Question #5392e - Socratic

    Dec 13, 2017 · Here's what I get. Step 1. Write the molecular equation "Fe" ("NO"_3)_3" (aq)"+ "3NH"_3" (aq)" + "3H"_2"O (l)" → "Fe (OH)"_3" (s)" + "3NH"_4"NO"_3" (aq)" Step 2 ...

  10. Question #53967 - Socratic

    a. HI (aq) rarr H^ (+) + I^- b. HNO_3 (aq) rarr H^ (+) + NO_3^- c. Ba (OH)_2 (aq) rarr Ba^ (2+) + 2HO^-. "Hydrogen iodide" is in fact a very strong acid; as is "nitric acid", HNO_3 (in fact the former is a …